The temperature of a brass part weighing 0.2 kg is 365 degrees, how much heat it will transfer to surrounding
| February 17, 2021 | education
The temperature of a brass part weighing 0.2 kg is 365 degrees, how much heat it will transfer to surrounding bodies, cooling down to a temperature of 15 degrees.
To find the heat transferred by a given brass part to the surrounding bodies during cooling, we will use the formula: Q = Cl * m * (tн – tк).
Constants and variables: Сл – specific heat capacity of brass (Сl = 400 J / (kg * K)); m is the mass of the part (m = 0.2 kg); tн – temperature before cooling (tн = 365 ºС); tк – final temperature (tк = 15 ºС).
Calculation: Q = Cl * m * (tn – tk) = 400 * 0.2 * (365 – 15) = 28 * 10 ^ 3 J = 28 kJ.
Answer: The surrounding bodies will receive 28 kJ of heat upon cooling the brass part.
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