The temperature of an iron part weighing 200 grams dropped from 70 to 50. How much heat did the part give off?

To find the heat that the taken iron part gave up during cooling, we will use the formula: Q = Czh * m * (t1 – t2).

Variables and constants: Szh – specific heat of iron (Szh = 452 J / (kg * K)); m is the mass (m = 200 g = 0.2 kg); t1 – temperature before cooling (t1 = 70 ºC); t2 – final temperature (t2 = 50 ºC).

Calculation: Q = Czh * m * (t1 – t2) = 452 * 0.2 * (70 – 50) = 1808 J.

Answer: The taken part gave 1808 J of heat.