The temperature of the heater is 150 and the refrigerator is 20 what work will an ideal engine

The temperature of the heater is 150 and the refrigerator is 20 what work will an ideal engine do if the working fluid receives 1.0 × 10 ^ 8 J of heat from the heater

To calculate the amount of work performed by the ideal motor used, we use the equality: 1 – Tx / Tn = η (engine efficiency) = A / Qn, from where we express: A = Qn * (1 – Tx / Tn).

Variables: Qн – heat received by the working fluid (Qн = 1 * 10 ^ 8 J); Тх – temperature of the engine refrigerator (Тх = 20 ºС = 293 K); Тн – heater temperature (Тн = 150 ºС = 423 К).

Let’s make a calculation: A = Qn * (1 – Tx / Tn) = 1 * 10 ^ 8 * (1 – 293/423) = 30.73 * 10 ^ 6 J = 30.73 MJ.

Answer: The ideal engine used will do a work of 30.73 MJ.