The temperature of the heater of an ideal heat engine is 127 ºС, the temperature of the refrigerator is 27 ºС.

| September 27, 2021 | education

The temperature of the heater of an ideal heat engine is 127 ºС, the temperature of the refrigerator is 27 ºС. The working body of the machine receives 3 MJ of heat from the heater every second. Determine the power of the machine.

To determine the power of the indicated ideal heat engine, we use the formula: N = A / t = (Qn – Qx) / t = (Qn – Qn * (1 – η)) / t = (Qn – Qn * (1 – (1 – Tx / Тн))) / t = (Qн – Qн * Тх / Тн) / t.

Variables: Тн (machine heater temperature) = 127 ºС (400 К); Тх (refrigerator temperature) = 27 ºС (300 К); Qн (heat from the heater) = 3 MJ (3 * 10 ^ 6 J); t (cycle time) = 1 s.

Calculation: N = (Qn – Qn * Tx / Tn) / t = (3 * 10 ^ 6 – 3 * 10 ^ 6 * 300/400) / 1 = 750 * 10 ^ 3 W = 750 kW.

Answer: The power of the specified heat engine is 750 kW.



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