The temperature of the heater of an ideal heat engine is 425 K, and the temperature of the refrigerator

The temperature of the heater of an ideal heat engine is 425 K, and the temperature of the refrigerator is 300 K. The engine receives 4 ∙ 10 ^ 4 J of heat from the heater. Calculate the work done by the working fluid of the engine.

To calculate the value of the work performed by the working fluid of the used engine, we apply the equality: 1 – Тх / Тн = η (efficiency) = Art / Qн, whence A = (1 – Тх / Тн) * Qн.

Preset variables: Тх – engine cooler temperature (Тх = 300 К); Тн – heater temperature (Тн = 425 К); Qн – heat received by the working fluid (Qн = 4 * 10 ^ 4 J).

Calculation: A = (1 – Tx / Tn) * Qn = (1 – 300/425) * 4 * 10 ^ 4 = 11.76 * 10 ^ 3 J = 11.76 kJ.

Answer: The working body of the engine used will perform work of 11.76 kJ.