The temperature of the heater of the heat engine is 127C, the temperature of the refrigerator is 7C.
The temperature of the heater of the heat engine is 127C, the temperature of the refrigerator is 7C. How will the useful coefficient of action change if the temperature of the refrigerator is reduced by 20C.
To find the change in the efficiency of a given heat engine, we use the ratio: k = η2 / η1 = (1 – (Tx – ΔT) / Tn) / (1 – Tx / Tn).
Values of variables: Тх – initial temperature of the refrigerator (Тх = 7 ºС = 280 К); ΔT – change (decrease) in the temperature of the refrigerator (ΔT = 20 ºС = 20 K); Тн – constant temperature of the heater (Тн = 127 ºС = 400 К).
Calculation: k = (1 – (Тх – ΔT) / Тн) / (1 – Тх / Тн) = (1 – (280 – 20) / 400) / (1 – 280/400) = 0.35 / 0, 3 = 1.167 p.
Answer: After lowering the temperature of the refrigerator, the efficiency will increase by 1.167 times.