The temperature of water with masses of m1 and m2 is equal to Т1 = 500С, Т2 = 00С, respectively.

| July 17, 2021 | education

The temperature of water with masses of m1 and m2 is equal to Т1 = 500С, Т2 = 00С, respectively. 1. In what ratio should two masses of water be mixed in order for the mixture to have a temperature of T3 = 200C? 2. If m1 = 3 kg, then what is m2? 3. In what ratio should two masses of water be mixed so that the mixture has a temperature of T3 = 300C? 4. If in this case m2 = 2 kg, then what is m1?

1) To determine in what ratio it is necessary to mix two masses of water so that the mixture has a temperature of T3 = 20 ° C, if it is known that the temperature of water with a mass of m1 and m2 is equal to T1 = 50 ° C, T2 = 0 ° C, respectively, we will compose the heat balance equation: s • m1 (Т1 – Т3) = с • m2 (Т3 – Т2), since the amount of heat transferred by hot water and received by cold water coincide in modulus. We get, 30 • m1 = 20 • m2; m1: m2 = 2/3. Answer: m1: m2 = 2/3 (B).
2) If m1 = 3 kg, then m2 = m1: 2/3 = 3 kg: 2/3 = 4.5 kg. Answer: 4.5 kg (A).
3) To determine in what ratio it is necessary to mix two masses of water so that the mixture has a temperature of T3 = 30 ° C, we compose a new heat balance equation: s • m1 (T1 – T3) = s • m2 (T3 – T2), we get 20 • m1 = 30 • m2; m1: m2 = 3/2. Answer: m1: m2 = 3/2 (D).
4) If in the second case m2 = 2 kg, then m1 = m2 • 3/2 = 2 kg • 3/2 = 3 kg. Answer: 3 kg (B).



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.