The thread pendulum oscillates at a frequency of 2 Hz. Determine the oscillation period and the number of oscillations per minute.

v = 2 Hz.

t = 1 min = 60 s.

T -?

n -?

The frequency of oscillations of the pendulum v is the number of oscillations in a time of 1 s. The oscillation frequency v is determined by the formula: v = n / t, where n is the number of oscillations during time t.

n = v * t.

n = 2 Hz * 60 s = 120.

The oscillation period T is the time of one complete oscillation. The oscillation period T is determined by the formula: T = t / n = 1 / v.

T = 1/2 Hz = 0.5 s.

The period T is the reciprocal of the frequency v.

Answer: the pendulum will make n = 120 oscillations, the oscillation period is T = 0.5 s.



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