The tornado moves at an average speed of 800 m / s, it was created at a distance of 80,000 km from

| August 5, 2021 | education

The tornado moves at an average speed of 800 m / s, it was created at a distance of 80,000 km from the city and for the first 40,000 km it moved at a speed of 1000 m / s. With what speed will he overcome the remaining 40,000 km to the city?

To find the speed with which the tornado must overcome the remaining 40,000 km of the path, we use the formula: Vav = S / (t1 + t2) = S / (S1 / V1 + S2 / V2) = S / (S / 2V1 + S / 2V2 ) = 1 / (1 / 2V1 + 1 / 2V2), whence 1 / Vav = 1 / 2V1 + 1 / 2V2; 1 / 2V2 = 1 / Vav – 1 / 2V1 and V2 = 1 / (2 * (1 / Vav – 1 / 2V1)).

Variables: Vav – average tornado speed (Vav = 800 m / s).

Calculation: V2 = 1 / (2 * (1 / Vav – 1 / 2V1)) = V2 = 1 / (2 * (1/800 – 1 / (2 * 1000))) = 666.67 m / s.

Answer: The tornado will overcome the remaining 40,000 km at a speed of 666.67 m / s (the task is conditional, since the average speed of a tornado is 40 … 60 m / s, and a distance of 80,000 km corresponds to double the length of the equator).



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