The total length of the edges of a rectangular parallelepiped = 612m. One of the edges is 54m less than the other
The total length of the edges of a rectangular parallelepiped = 612m. One of the edges is 54m less than the other and 30m more than the third. Find the dimensions of the parallelepiped. d) the lower edge of the parallelepiped is 25dm long and 24dm wide, 10dm high. e) the lower edge of the parallelepiped is 70cm long and 33cm wide, 6cm high.
1) Having designated one dimension as a, then the other 2 will be equal: (a + 54); (a – 30. Then we get the perimeter: 4 * a + 4 * (a – 30 + 4 * (a + 54) = 4 * (a + a – 30 + a + 54) = 4 * (3 * a + 24 ) = 612 (m).
4 * 3 * (a + 8) = 612; a + 8 = 612: 12 = 43, then the other two sides are equal: a + 54 = 43 + 54 = 97 m; a – 30 = 43 – 30 = 13 m.
Parallelepiped measurements: 13 m, 43 m, 97 m.
2) Length – 25 dm, height – 10 dm; width – 24 dm. Face area: 2 * 25 dm * 10 dm + 2 * 24 dm * 10 dm + 2 * 25 dm * 24 dm = 1200 + 500 + 480 = 2180 dm ^ 2.