The total surface area of a regular quadrangular prism is 102 dm² and the lateral surface area
The total surface area of a regular quadrangular prism is 102 dm² and the lateral surface area is 84 dm². Find the height of the prism.
The total surface area of the prism is equal to the sum of the lateral surface area and the area of the two bases. Find the area of the base:
Sb = (Sp – Sbok): 2 = (102 – 84): 2 = 18: 2 = 9 dm².
The base of a regular prism is a square with an area of 9 dm². This means that the side of the base of the prism will be 3 dm (3 * 3 = 9).
The side surface consists of four equal faces. Let’s find the area of one face:
Sgr = Sside: 4 = 84: 4 = 21 dm².
The face of a straight prism is a rectangle with sides equal to the side of the base and the height.
3 * h = 21.
Hence h = 7 dm.
Answer: The height of the prism is 7 dm.