The tourist climbed a hill with a height of h = 10 m with an angle of 30 degrees, and then descended

The tourist climbed a hill with a height of h = 10 m with an angle of 30 degrees, and then descended from the same height along a slope with an angle of 60 degrees. What are the tourist’s path and travel module equal to?

Slope length on the rise:
L1 = h / sin 30 = 10 / (1/2) = 20 m;
Descent slope length:
L2 = h / sin 60 = 10 / (√3 / 2) = 11.55 m;
Projection:
S1 = h / tg30;
Way:
L = L1 + L2 = 20 + 11.55 = 31.55 m:
Projection:
S2 = h / tg 60;
Moving:
S = S1 + S2 = h / tg30 + h / tg60 = 10 * (1 / tg30 + 1 / tg60) = 23 m.