The tourist walked along a mountain trail, moving at a speed of 2 km / h, and then returned to the place

The tourist walked along a mountain trail, moving at a speed of 2 km / h, and then returned to the place of his start moving at a speed of 6 km / h. What was the average speed of a tourist along the way?

Average tourist speed:
Vav. = S / t, where S is the path traveled by the tourist (S = S1 + S2, where S1 = S2 = 0.5 S), t is the travel time of the tourist (t = t1 + t2).
t1 = S1 / V1, t2 = S2 / V2, where V1 is the speed in one direction (V1 = 2 km / h), V2 is the speed in the opposite direction (V2 = 6 km / h).
Let’s calculate the average speed of movement:
Vav. = S / t = (S1 + S2) / (S1 / V1 + S2 / V2) = S / (0.5S / 2 + 0.5S / 6) = 1 / 0.333 = 3 km / h.
Answer: The average speed of a tourist is 3 km / h.