The tracked tractor weighing 6,610 kg has a supporting area of both tracks of 1.4 m2.

The tracked tractor weighing 6,610 kg has a supporting area of both tracks of 1.4 m2. Determine the ground pressure of this tractor. How many times is it more than the pressure exerted by the boy?

To solve this problem, we will use the formula:
p = F / S,
where p is the pressure of the tractor tracks on the soil, F is the force of gravity, S is the area of the tracks.
Given:
m = 6610 kg
S = 1.4 m2
g = 10 N / kg
Find: p
Decision:
P = F / S = (mg) / S = (6610 * 10) / 1.4 = 47210 Pa = 47 kPa
Answer: p = 47 kPa; about 3 times