The traction force of the car engine is 800N, its mass is 1000 kg. Friction coefficient 0.1.

The traction force of the car engine is 800N, its mass is 1000 kg. Friction coefficient 0.1. Determine the type of vehicle movement.

To find out the type of movement of the specified car, we determine its acceleration: m * a = Ftyag – Ftr, whence we express: a = (Ftyag – Ftr) / m = (Ftyag – μ * m * g) / m.

Const: g – acceleration due to gravity (g ≈ 9.81 m / s2).

Data: Ftyag – the thrust force of the motor (Ftyag = 800 N); m is the mass of the vehicle (m = 1000 kg); μ – coefficient of friction (μ = 0.1).

Calculation: a = (Ftyag – μ * m * g) / m = (800 – 0.1 * 1000 * 9.81) / 1000 = -0.181 m / s2.

Since a <0, then the specified car must move equally slowly until it stops (V = 0 m / s).

Answer: The specified car moves with equal slowness (a <0).