The traction force of the car is 1000N, the force of resistance to its movement is 700 N. Determine the equal acting forces.

Task data: Ftyag. (traction force of the car) = 1000 N; Fc. (resistance to movement) = 700 N.

Since the vectors of the thrust force and the force of resistance to motion are collinear and oppositely directed, the resultant of these forces is equal to: = Ftyag. – Fc. = 1000 – 700 = 300 N.

Answer: The resultant forces acting on the vehicle in question is 300 N.



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