The traction force of the locomotive is 2.4 * 10 ^ 5N, the power is 3 * 10 ^ 3 kW.

The traction force of the locomotive is 2.4 * 10 ^ 5N, the power is 3 * 10 ^ 3 kW. How long does it take for a train to cover the distance between two stations 10.8 km, moving evenly?

Initial data: F (locomotive traction force) = 2.4 * 10 ^ 5 N; N (locomotive power) = 3 * 10 ^ 3 kW = 3 * 10 ^ 6 W; S (distance between stations) = 10.8 km = 10800 m; the locomotive movement is uniform.

1) Let’s calculate the speed with which the locomotive was moving:

N = F * V; V = N / F = 3 * 10 ^ 6 / (2.4 * 10 ^ 5) = 12.5 m / s.

2) Let’s calculate the time of movement of a diesel locomotive between two stations:

t = S / V = 10800 / 12.5 = 864 s = 14 min 24 s.

Answer: The locomotive will cover the distance between the two stations in 14 minutes 24 seconds.