The tractor exerts a pressure of 60 kPa on the soil. What is the area of contact of the wheels

The tractor exerts a pressure of 60 kPa on the soil. What is the area of contact of the wheels with the soil if the weight of the tractor is 4 tons?

To find the value of the area of contact of the wheels of a given tractor with the soil, we apply the formula: P = Ftyazh / S = m * g / S, whence S = m * g / P.

Constants and variables: m – tractor weight (m = 4 t = 4 * 10 ^ 3 kg); g – acceleration due to gravity (g ≈ 9.8 m / s2); P – applied pressure (P = 60 kPa = 60 * 10 ^ 3 Pa).

Calculation: S = m * g / P = 4 * 10 ^ 3 * 9.8 / (60 * 10 ^ 3) = 0.653 m2.

Answer: The contact area of the wheeled tractor with the ground is 0.653 m2.