The tractor moves the platform at a speed of 7.2 km / h, developing a traction gain of 25 kN.

The tractor moves the platform at a speed of 7.2 km / h, developing a traction gain of 25 kN. What kind of work does the tractor do in 10 minutes?

Initial data: V (speed of movement of the platform by the tractor) = 7.2 km / h (2 m / s); F (tractive effort that the tractor develops) = 25 kN (25 * 10 ^ 3 N); t (duration of the tractor operation) = 10 min (600 s).

The work that the tractor will perform is determined by the formula: A = N * t = F * V * t.

Calculation: A = 25 * 10 ^ 3 * 2 * 600 = 30 * 10 ^ 6 J (30 MJ).

Answer: In 10 minutes, the tractor will perform work to move the platform of 30 MJ.



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