The tractor traveled 600 m in the first 5 minutes. Which way the tractor will drive at the same speed in 0.5 hours.

Condition:
t1 = 5 min. = 300 sec.
t2 = 0.5 h. = 30 minutes = 1800 sec.
S1 = 600 m
Find: S2 -? m

Decision :

1 solution:
V1 = S1 / t1
V1 = 600/300 = 2 (m / s)
since speed constant V1 = V2 = 2 (m / s)
S2 = V2 * t2
S2 = 2 * 1800 = 3600 (m)

2 way to solve:
since constant speed
the travel time increased 6 times, hence it follows that
the distance will increase 6 times.
t2 = 6t1; t2 = 1800 sec.
S2 = 6 * S1
S2 = 6 * 600 = 3600 (m)
Answer: 3600 m