Task data: m (tractor weight) = 6000 kg; S (support area of tractor tracks) = 2000 cm2.
Reference values: g (acceleration due to gravity) = 9.81 m / s2 ≈ 10 m / s2.
SI system: S = 2000 cm2 = 2000 * 10-4 m2 = 0.2 m2.
1) Let’s calculate the force with which the mass of the tractor acts on the soil: F = m * g = 6000 * 10 = 60,000 N.
2) Determine the pressure of the tractor on the soil: P = F / S = 60,000 / 0.2 = 300,000 Pa or 300 kPa.
Answer: The tractor will exert a pressure of 300 kPa on the soil.
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