The trailer is detached from the vehicle, which is traveling at a constant speed. It is known that before its full stop

| February 5, 2021 | education

The trailer is detached from the vehicle, which is traveling at a constant speed. It is known that before its full stop, the trailer, moving at an equal rate, traveled 200 m. Determine the distance that the car has traveled during this time

V = 0 m / s.

Sп = 200 m.

Sa -?

The movement of the trailer Sп to a full stop will be determined by the formula: Sп = V0 ^ 2/2 * a, where V0 is the speed of the trailer at the moment of uncoupling, and is the acceleration of the trailer.

Let us express the acceleration of the trailer a: a = V0 / t.

Sп = V0 ^ 2 * t / 2 * V0 = V0 * t / 2.

Let us express the travel time of the trailer t until a complete stop: t = 2 * Sп / V0.

Let us find the distance Sа, which the car traveled, moving uniformly with the speed V0 and time t.

Sa = V0 * t = V0 * 2 * Sп / V0 = 2 * Sп.

Sa = 2 * 200 m = 400 m.

Answer: the car has traveled the distance Sa = 400 m.



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