The train approaches the station at a speed of 36 km / h and stops one minute

The train approaches the station at a speed of 36 km / h and stops one minute after the start of braking. With what acceleration did the train move?

Given:

V0 = 36 km / h = 10 m / s – the speed of the train before braking;

t = 1 m = 60 s – train deceleration time;

It is required to find a – the acceleration with which the train was moving.

a = (V1 – V0) / t, where V1 is the speed at the end of the time period. Since the train was slowing down, V1 = 0.

a = 0 – 10/60 = -10/60 = -0.17 m / s ^ 2. A negative sign of acceleration indicates the nature of the movement, namely braking.

Answer: Acceleration is 0.17 m / s ^ 2.