The train begins to move along the straight section of the track with uniform acceleration with an acceleration

The train begins to move along the straight section of the track with uniform acceleration with an acceleration of 1.6 m / s2. How long will the train travel in 20 seconds? What speed will it reach during this time?

Given: rectilinear uniformly accelerated motion; V0 (initial speed) = 0 m / s; a (acceleration) = 1.6 m / s2; t (considered travel time) = 20 s.

1) Determine the path covered in 20 s: S = V0 * t + a * t ^ 2/2 = 0 * 20 + 1.6 * 20 ^ 2/2 = 320 m.

2) Let’s calculate the speed achieved in 20 s of acceleration: V = V0 + a * t = 0 + 1.6 * 20 = 32 m / s.

Check: S = (V ^ 2 – V0 ^ 2) / 2a = (32 ^ 2 – 0 ^ 2) / (2 * 1.6) = 1024 / 3.2 = 320 m (correct).

Answer: In 20 seconds of acceleration, the train will reach a speed of 32 m / s and cover a distance of 320 m.