The train develops a speed of 6 m / s 50 s after the start of movement from the station
| June 30, 2021 | education
The train develops a speed of 6 m / s 50 s after the start of movement from the station, calculate the acceleration of the train.
These tasks: t (time elapsed after the given train left the station) = 50 s; V (the speed that the train developed) = 6 m / s.
To calculate the acceleration of a given train, we use the formula: V = V0 + a * t, whence a = (V – V0) / t = (V – 0) / t = V / t.
Calculation: a = 6/50 = 0.12 m / s2.
Answer: The given train had to move with an acceleration of 0.12 m / s2.
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