The train in 10 s after the start of movement acquires a speed of 0.6 m / s.

The train in 10 s after the start of movement acquires a speed of 0.6 m / s. After what time from the start of movement the speed of the train will be equal to 3m / s.

Data: t1 (the first segment of the train movement) = 10 s; V1 (the speed that the train acquired after time t1) = 0.6 m / s; V2 (the speed that the train acquired after time t2) = 3 m / s; V0 (initial train speed) = 0 m / s.

Since the acceleration of the train is constant, the time from the start of movement, when its speed is equal to 3 m / s, is determined from the equality: a = V1 / t1 = V2 / t2, whence t2 = V2 * t1 / V1.

Calculation: t2 = 3 * 10 / 0.6 = 50 s.

Answer: The train speed will become 3 m / s after 50 seconds.