The train increases its speed from v = 30 km / h to V = 60 km / h in time t = 8 s.

| September 7, 2021 | education

The train increases its speed from v = 30 km / h to V = 60 km / h in time t = 8 s. What distance will the train travel during this time? Consider the acceleration of the train constant.

v = 30 km / h = 8.3 m / s.

V = 60 km / h = 16.6 m / s.

t = 8 s.

S -?

With uniformly accelerated movement, the traversed path S is determined by the formula: S = v * t + a * t ^ 2/2, where v is the initial speed of movement, a is the acceleration during movement, t is the time of movement.

We find the acceleration of the train a by the formula: a = (V – v) / t, where V is the final speed during acceleration of the train.

a = (16.6 m / s – 8.3 m / s) / 8 s = 1 m / s2.

S = 8.3 m / s * 8 s + 1 m / s2 * (8 s) ^ 2/2 = 66.4 m + 32 m = 98.4 m.

Answer: during acceleration, the train covered the distance S = 98.4 m.



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