The train is moving at a speed of 15m / s. What is the distance the train will cover in 10 seconds.
| August 25, 2021 | education
Given: V0 (speed before braking) = 15 m / s; t (deceleration duration) = 10 s; a (acceleration of a given train) = 0.5 m / s2.
The desired path that a given train will pass in 10 s of braking is calculated by the formula (slow motion): S = V0 * t – 0.5 * a * t ^ 2.
Calculation: S = 15 * 10 – 0.5 * 0.5 * 10 ^ 2 = 150 – 25 = 125 m.
Answer: In 10 seconds of braking, the given train covered a distance of 125 m.
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