The train is moving in a straight line at a speed of 15m / s. How much distance will it take in 10s

The train is moving in a straight line at a speed of 15m / s. How much distance will it take in 10s from braking, which occurs with an acceleration of 0.5m / s.

V0 = 15 m / s.

t = 10 s.

a = 0.5 m / s2.

S -?

With uniformly accelerated motion, when the body decreases its speed (decelerates), the path of the body S is determined by the formula: S = V0 * t – a * t ^ 2/2, where V0 is the initial speed of motion, a is the acceleration of the body during motion, t is the time braking.

S = 15 m / s * 10 s – 0.5 m / s2 * (10 s) ^ 2/2 = 150 m – 25 m = 125 m.

Answer: the braking distance of the train was S = 125 m.



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