The train, leaving the station, covered a distance of 562.5 m and developed a speed of 27 km / h. Find the acceleration of the train.

These tasks: S (the distance traveled by the train after leaving the station) = 562.5 m; V0 (initial speed) = 0 m / s; V (speed reached by the train) = 27 km / h (in SI system V = 7.5 m / s).

To calculate the acceleration of a given train, apply the formula: S = (V ^ 2 – V0 ^ 2) / 2a = (V ^ 2 – 0 ^ 2) / 2a, whence a = V ^ 2 / 2S.

Calculation: a = 7.5 ^ 2 / (2 * 562.5) = 0.05 m / s2.

Answer: The train, leaving the station, moved with an acceleration of 0.05 m / s2.