The train left the station and covered a distance of 562.5m. How long did it take for this if he was

The train left the station and covered a distance of 562.5m. How long did it take for this if he was moving with an acceleration of 5m / s ^ 2.

These tasks: the train under consideration departed from the station (V0 (initial speed) = 0 m / s); S (distance traveled) = 562.5 m; a (acceleration of the train under consideration) = 5 m / s2.

The time required for the train under consideration to travel a given path is expressed from the formula: S = a * t2 / 2, whence t = √ (2S / a).

Let’s perform the calculation: t = √ (2 * 562.5 / 5) = 15 s.

Answer: The train in question took 15 seconds to travel 562.5 m.