The train moved from the station with an acceleration of 0.5 m / s and reached a speed of 60

The train moved from the station with an acceleration of 0.5 m / s and reached a speed of 60 km / h, which is the distance covered.

V0 = 0 m / s.

V = 60 km / h = 16.7 m / s.

a = 0.5 m / s2.

S -?

When moving with constant acceleration, the path S traveled by the body is determined by the formula: S = V0 * t + a * t ^ 2/2, where V0 is the initial speed of the train, t is the time of movement of the train, a is the acceleration of the train.

According to the definition, the acceleration a shows how quickly the speed of the train changes during movement: a = (V – V0) / t.

t = (V – V0) / a.

Since the train starts its movement from the station, its initial speed V0 = 0 m / s.

The formulas will take the form: S = a * t ^ 2/2, t = V / a.

S = a * V ^ 2/2 * a ^ 2 = V ^ 2/2 * a.

S = (16.7 m / s) ^ 2/2 * 0.5 m / s2 = 279 m.

Answer: the train passes the track S = 279 m.