The train moves with an initial speed v0 = 36 km / h with an acceleration a = 0.2 m / s ^ 2

The train moves with an initial speed v0 = 36 km / h with an acceleration a = 0.2 m / s ^ 2. How long will its speed double and how long will it take during this time.

Initial data: V0 (initial speed) = 36 km / h (in SI system V0 = 10 m / s); a (acceleration of a given train) = 0.2 m / s2; V (required speed) = 2V0.

1) The duration of the train increasing its speed: t = (V – V0) / a = (2V0 – V0) / a = V0 / a = 10 / 0.2 = 50 s.

2) Distance covered in 50 s: S = (V + V0) * t / 2 = (2V0 + V0) * t / 2 = 3V0 * t / 2 = 3 * 10 * 50/2 = 750 m.

Answer: The given train increased its speed in 50 s and traveled 750 m at the same time.