The train, moving at a speed of 40 m / s, began to slow down.

The train, moving at a speed of 40 m / s, began to slow down. What will its speed be equal to in 2min, if the acceleration during deceleration is 0.2m / s².

Task data: V0 (speed of a given train before braking) = 40 m / s; t (deceleration duration) = 2 min (in SI t = 120 s); a (acceleration during deceleration) = 0.2 m / s2.

The speed at which a given train will move in 2 minutes is determined by the formula: V = V0 – a * t.

Let’s calculate: V = 40 – 0.2 * 120 = 16 m / s.

Answer: After 2 minutes of deceleration, the speed of the given train will be 16 m / s.



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