The train, moving evenly at a speed of 57 km / h, passes by a pedestrian walking parallel

The train, moving evenly at a speed of 57 km / h, passes by a pedestrian walking parallel to the tracks at a speed of 3 km / h towards the train in 33 seconds. Find the length of the train

1. Since the train is going towards the walking pedestrian, the speed of the train relative to the pedestrian will be:

57 + 3 = 60 km / h.

2. Let’s convert the speed from km / h to m / s:

60 x 1000: 3600 = 600/36 = 50/3 m / s.

For the convenience of further calculations, we deliberately did not convert the incorrect fraction to the correct one.

3. Since the train passes by the pedestrian in 33 seconds, the length of the train is:

33 x 50/3 = 1650/3 = 550 meters.

Answer: the length of the train is 550 meters.



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