# The train, moving evenly at a speed of 75 km / h, passes a pedestrian walking parallel to the tracks at a speed of 3 km / h

January 15, 2021 | education

| **The train, moving evenly at a speed of 75 km / h, passes a pedestrian walking parallel to the tracks at a speed of 3 km / h towards the train, in 30 seconds. Find the length of the train in meters.**

1. Let’s calculate the speed of the train relative to the pedestrian moving towards it.

75 km / h + 3 km / h = 78 km / h.

2. Determine how much is 30 seconds in hours.

30 sec = 30: (60 * 60) h = 30/3600 = 1/120 h.

3. Let’s calculate the length of the train.

78 km / h * 1/120 h = 0.65 km.

4. Determine how many meters is 0.65 km.

0.65 * 1000 = 650 meters.

Answer. The train length is 650 meters.

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