The train, rolling up the hill, travels 300 meters in 25 seconds and at the end

The train, rolling up the hill, travels 300 meters in 25 seconds and at the end of the ascent has a speed of 18 km / h. What was the speed of the train at the beginning of the rise?

These tasks: S (the distance traveled by a given train when moving uphill) = 300 m; t (duration of movement) = 25 s; V (speed at the end of the ascent) = 18 km / h (SI V = 5 m / s).

To determine the speed of a given train at the beginning of the ascent, we use the formula: S = (V + V0) * t / 2, whence V + V0 = 2S / t and V0 = 2S / t – V.

Let’s calculate: V0 = 2 * 300/25 – 5 = 19 m / s.

Answer: At the beginning of the ascent, the given train had a speed of 19 m / s.