The train travels at a speed of 20 m / s. What will be the speed of the train after braking

The train travels at a speed of 20 m / s. What will be the speed of the train after braking, which occurs with an acceleration of 0.25 m / s2 for 20 seconds.

These tasks: V0 (the speed with which the train under consideration was going) = 20 m / s; a (acceleration with which braking occurred) = 0.25 m / s2; t (deceleration duration) = 20 s; slow motion.

The speed of the train in question after braking is determined by the formula: V = V0 – a * t.

Let’s perform the calculation: V = 20 – 0.25 * 20 = 20 – 5 = 15 m / s.

Answer: After 20 seconds of braking, the train in question will have a speed of 15 m / s.