# The train was delayed on the way for 6 minutes and eliminated the delay on the stretch of 20 km by passing

The train was delayed on the way for 6 minutes and eliminated the delay on the stretch of 20 km by passing it at a speed of 10 km / h more than the one that was on the schedule, determine the speed of the train on this stretch according to the schedule

Decision:
x – planned speed
x + 10 – speed on the stretch to eliminate delay
t = 6 min = 1/10 = 0.1 h – stop time and, at the same time, time to eliminate delay
s = 20 km – haul
s = v * t – formula of the path from speed and time
20 = (x + 10) * 0.1
200 = x + 10
x = 190 km / h – the planned speed on this stretch according to the schedule

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