The tram engines are started gradually over 10 seconds. In this case, the tram runs 20 meters. Find the acceleration of the tram.

V0 = 0 m / s.

t = 10 s.

S = 20 m.

a -?

Acceleration of a tram, and is called a vector physical quantity, which is determined by the ratio of the change in speed ΔV to the time t during which this change occurs:

a = (V – V0) / t.

The path of the tram with uniform acceleration S is expressed by the formula: S = V0 * t + a * t ^ 2/2.

Since the tram starts its movement from a state of rest V0 = 0 m / s, the formulas will take the form: a = V / t, S = a * t ^ 2/2

a = 2 * S / t ^ 2.

a = 2 * 20 m / (10 s) ^ 2 = 0.4 m / s2.

Answer: the tram starts moving with an acceleration of a = 0.4 m / s2.



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