The tram motor develops a traction force of 1.3 kN at a voltage of 600 V.
| February 17, 2021 | education
The tram motor develops a traction force of 1.3 kN at a voltage of 600 V. What amperage does it consume at a speed of 18 km / h, if the engine efficiency is 75%
Initial data: F (traction force developed by the tram engine) = 1.3 kN (1.3 * 10 ^ 3 N); U (effective voltage) = 600 V; V (tram speed) = 18 km / h (5 m / s); η (tram engine efficiency) = 75% (0.75).
The current strength consumed by the tram engine is determined from the formula: η = Nп / Nз = F * V / (U * I), whence I = F * V / (U * η).
Calculation: I = 1.3 * 10 ^ 3 * 5 / (600 * 0.75) = 14.4 A.
Answer: The current in the tram motor will be 14.4 A.
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