The tram was moving at a speed of 18 m / s and was decelerated for 2 minutes
| September 4, 2021 | education
The tram was moving at a speed of 18 m / s and was decelerated for 2 minutes. Find the length of the braking distance, considering the movement of the tram equally slow.
To find the value of the stopping distance of the specified tram, we apply the formula: S = (Vн – Vк) * t / 2.
Variables: Vн – initial speed (Vн = 18 m / s); Vк – reached speed (Vк = 0 m / s, the tram will stop); t – tram deceleration time (t = 2 min = 120 s).
Calculation: S = (Vн – Vк) * t / 2 = (18 – 0) * 120/2 = 1080 m.
Answer: The braking distance of the indicated tram is 1080 m.
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