The traveler rode a bicycle for 2 hours, and then walked for 6 hours. How many times is the average speed of the entire path
The traveler rode a bicycle for 2 hours, and then walked for 6 hours. How many times is the average speed of the entire path greater than the speed of walking? The speed when cycling is 2 times the speed when walking.
1. Average speed by definition Vav = S / T, where S is the full path, T is the total time during which this path is covered.
2. Let V1 be the walking speed. Then V2 = 2 * V1 is the speed of the bike.
3. Path S1, which the traveler traveled by bicycle, will be defined as:
S1 = V2 * 2 = 2 * V1 * 2 = 4 * V1.
4. Path S2, which the traveler walked, is defined as:
S2 = V1 * 6.
5. Full path S = S1 + S2 = 4 * V1 + 6 * V1 = 10 * V1.
6. Total time T = 2 + 6 = 8.
7. Average speed Vav = 10 * V1 / 8 = 1.25 * V1.
8. The ratio of the average speed to the speed when walking on foot Vav / V1 = 1.25.
Answer: The average speed is 1.25 times the speed when traveling on foot.