The triangle has an ID of 30 ° inside and one outside 40 °. Find the rest of the inside corners of the triangle.

The solution of the problem:
In the specification, a triangle is given, for which one inner corner and one outer corner is known. It is known that the sum of the outer and inner angles of a triangle is 180 degrees.
1. Find what the other inner corner of the triangle is equal to.
180-40 = 140 degrees.
The sum of all the interior angles of any triangle is 180 degrees.
2. Find what is the third inner corner of the triangle.
180-30-140 = 10 degrees.
Answer: The second angle of the triangle is 140 degrees, the third angle is 10 degrees.