The triangle has one of the inner corners of 30 degrees and One of the outer corners of 40

The triangle has one of the inner corners of 30 degrees and One of the outer corners of 40 degrees Find the other inner corners of the triangle.

Given triangle ABC. Angle A is 30 degrees. Angle C will be 180-40 = 140 degrees, since its outer angle is 40 degrees, and its outer and inner angles are 180 degrees.
We know what the two angles of a triangle are equal to, and we know that the sum of all three angles in a triangle is 180 degrees.
Find out what the third angle of the triangle is equal to, angle B.
180- (140 + 30) = 10 degrees.
Answer: in this triangle, angle A is 30 degrees, angle B is 10 degrees, angle C is 140 degrees.



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