The trolley from the rest position passed 6.25 m with an acceleration of 0.32 m / s².
| June 25, 2021 | education
The trolley from the rest position passed 6.25 m with an acceleration of 0.32 m / s². Determine the final speed of the trolley and the time of its movement.
To find the final speed of a given trolley and the duration of its movement, we will use the formulas: S = V ^ 2 / 2a and V = a * t.
Values of variables: S – the path covered by the cart (S = 6.25 m); a – acceleration (a = 0.32 m / s2).
Calculation: a) Final speed: V = √ (2a * S) = √ (2 * 0.32 * 6.25) = 2 m / s.
b) Duration of movement: t = V / a = 2 / 0.32 = 6.25 s.
Check: S = (V + V0) * t / 2 = (2 + 0) * 6.25 / 2 = 6.25 m (correct).
Answer: The cart reached a speed of 2 m / s in 6.25 s.
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