The trolley, the weight of which together with the payload P = 8500 N, when moving along a horizontal track

| May 22, 2021 | education

The trolley, the weight of which together with the payload P = 8500 N, when moving along a horizontal track, experiences resistance, the value of which is 0.01P. The worker pushes the trolley with a force of F = 170 N. How long will the worker give the trolley a speed of v = 0.6 m / s?

Given: P (weight of the considered trolley with payload) = 8500 N; F (resistance force) = 0.01Р; F (acting force) = 170 N; V (required speed) = 0.6 m / s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Determine the acceleration of the trolley under consideration: m * a = P * a / g = F – Fsopr. = F – 0.01P and a = (F – 0.01P) * g / P = (170 – 0.01 * 8500) * 10/8500 = 0.1 m / s2.

2) Determine the duration of the trolley acceleration: V = V0 + a * t = 0 + a * t and t = V / a = 0.6 * 0.1 = 6 s.



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