The trolley weighing 15 kg brakes, moving uniformly under the action of a force of 9N.
| April 26, 2021 | education
The trolley weighing 15 kg brakes, moving uniformly under the action of a force of 9N. Write down the equation of its motion if it is known that the initial coordinate of the cart is X0 = 16 m, and the initial velocity is Vx = 8 m / s.
Task data: m (weight of the considered cart) = 15 kg; F (force acting on the cart) = 9 N; x0 (initial coordinate of the cart) = 16 m; Vx (initial velocity) = 8 m / s.
1) Find the acceleration of the given trolley: ax = F / m = 9/15 = 0.6 m / s2.
2) We write the equation of the movement of a given cart: S (t) = x0 + Vx * t + a * t ^ 2/2 = 16 + 8t + 0.6 * t ^ 2/2 = 16 + 8t + 0.3t ^ 2 …
Answer: The equation of motion of a given trolley has the form: S (t) = 16 + 8t + 0.3t ^ 2.
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