The trolleybus covered 120 m in 10 s. What speed did it acquire at the end of the track

| February 26, 2021 | education

The trolleybus covered 120 m in 10 s. What speed did it acquire at the end of the track and with what acceleration did it move if the initial speed was 10 m / s?

To find the speed and constant acceleration acquired by the trolleybus, we will use the formulas: S = (Vн + Vк) * t / 2, whence Vк = 2S / t – Vн and а = (Vк – Vн) / t.

Variables: S – the track covered by the trolleybus (S = 120 m); t – elapsed time (t = 10 s); Vн – the initial speed of the trolleybus (Vн = 10 m / s).

Calculation: a) acquired speed: Vк = 2S / t – Vн = 2 * 120/10 – 10 = 14 m / s;

b) trolleybus acceleration: a = (Vk – Vn) / t = (14 – 10) / 10 = 0.4 m / s2.

Check: S = Vn * t + a * t ^ 2/2 = 10 * 10 + 0.4 * 10 ^ 2/2 = 120 m (correct).

Answer: The trolleybus moved with an acceleration of 0.4 m / s2 and acquired a speed of 14 m / s.



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