The trolleybus covered 120m in 12 seconds, what speed it acquired at the end of the track and with what acceleration

The trolleybus covered 120m in 12 seconds, what speed it acquired at the end of the track and with what acceleration it moved if the initial speed was 10 m / s.

Distance traveled by trolleybus:
S = V0 * t + a * t² / 2, where S is the distance covered by the trolleybus (S = 120 m), V0 is the initial speed (V0 = 10 m / s), and is the acceleration of the trolleybus (m / s²), t – travel time (t = 12 s).
Let’s express and calculate the acceleration:
a * t² / 2 = S – V0 * t.
a = 2 * (S – V0 * t) / t² = 2 * (120 – 10 * 12) / 12² = 2 * 0 / 12² = 0 m / s².
Since a = 0 m / s², the movement is uniform and V = V0 = 10 m / s.
Answer: Acceleration is 0 m / s², final speed is 10 m / s.